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8x^2-6x=2
We move all terms to the left:
8x^2-6x-(2)=0
a = 8; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·8·(-2)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-10}{2*8}=\frac{-4}{16} =-1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+10}{2*8}=\frac{16}{16} =1 $
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